a/sinA = b/sinB = 2
a+b= 2(sinA + sinB)
=2[sinA + sin(120° - A) ]
=3sinA + √3 cosA
=√12 sin(A+α)
最大值=2√3
在三角形ABC中,AB=根号3,角ACB=60°,求AC+AB的最大值
在三角形ABC中,AB=根号3,角ACB=60°,求AC+AB的最大值
数学人气:905 ℃时间:2020-04-01 03:35:40
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