原式=1/(x+3)-(x-1)/2(x+3)-6/(x+3)(x-3)
=(2x-6-x²+4x-3-12)/2(x+3)(x-3)
=(-x²+6x-21)/2(x+3)(x-3)
=(-x²+6x-21)/(2x²-18)
1/x+3+1-x/6+2x-6/x^2-9. 分式加减
1/x+3+1-x/6+2x-6/x^2-9. 分式加减
数学人气：940 ℃时间：2020-02-06 01:19:44
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