如图所示,在正方形ABCD中,M是CD的中点,E是CD上一点,且∠BAE=2∠DAM.求证:AE=BC+CE.
如图所示,在正方形ABCD中,M是CD的中点,E是CD上一点,且∠BAE=2∠DAM.求证:AE=BC+CE.
数学人气:411 ℃时间:2019-12-14 02:51:43
优质解答
证明:如图,延长AB到F,使BF=CE,连接EF与BC相交于点N,在△BFN和△CEN中,∠FBN=∠C=90°∠BNF=∠CNEBF=CE,∴△BFN≌△CEN(AAS),∴BN=CN,EN=FN,又∵M是CD的中点,∴∠BAN=∠DAM,∵∠BAE=2∠DAM,∴∠BAN=∠...
我来回答
类似推荐
猜你喜欢
- 1嫦娥二号 开始绕月时为啥是椭圆轨道,后来变成圆形轨道
- 21+a+ab分之x+1+b+bc分之x +1+c+ac分之x ,已知abc=1,解方程
- 3The students are going out of the classroom in three and fours.
- 458+52+56+53+54+51+57=
- 5单选The doctor warned him __.A.not smoke B.not to smokeC.don't smokeD.should not smoke
- 6形容工作累有什么句子
- 7五年级课文《彩色的非洲》中与之相互呼应的句子是
- 8汉语翻译 If you venture nothing ,you will have nothing .
- 9...I heard they went skiing last winter ....It ------have been true because there was little
- 10fill in the blanks with the words and expressions in the table.是什么意思?