(tan²α-cot²α)/(sin²α-cos²α)
=(sin²α/cos²α-cos²α/sin²α)/(sin²α-cos²α)
=(sin⁴α-cos⁴α)/[sin²αcos²α(sin²α-cos²α)] 这一步是分子分母同乘以sin²αcos²α
=(sin²α+cos²α)(sin²α-cos²α)/[sin²αcos²α(sin²α-cos²α)] 注意sin²α+cos²α=1
=1/(sin²αcos²α)
=sec²αcsc²α,等式成立.
(tan^2α-cot^2α)/(sin^2α-cos^2α)=sec^2α•csc^2α
(tan^2α-cot^2α)/(sin^2α-cos^2α)=sec^2α•csc^2α
数学人气:565 ℃时间:2019-11-18 07:03:30
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