s/(s/2v1+s/2v2)
=s/[（v1+v2）s/2v1v2]
=s*2v1v2/[（v1+v2）s]
=2*v1v2/(v1+v2)
为什么s/(s/2v1+s/2v2),得出的结果就是2*v1v2/(v1+v2)
为什么s/(s/2v1+s/2v2),得出的结果就是2*v1v2/(v1+v2)
怎么算得?
怎么算得?
其他人气：210 ℃时间：2020-02-02 17:09:04
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