(2x-3)^2-(2y+1)^2=48
(2x-3+2y+1)(2x-3-2y-1)=48
-2(2x-2y-4)=48
-(x-y-2)=12
-x+y+2=12
2y+2=12
y=5,x=-5
(2x-3)的平方-(2y+1)的平方=48,求x和y
(2x-3)的平方-(2y+1)的平方=48,求x和y
x和y互为相反数
x和y互为相反数
数学人气:958 ℃时间:2019-09-29 04:09:33
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