解不等式(3-4x)(x的平方+x+2)分之x(x-1)(x-2)的三次方(x平方-1)(x三次方-1)大于0

x(x-1)(x-2)³(x+1)(x-1)(x-1)(x²+x+1)/[(3-4x)(x²+x+2)]>0x(x-1)³(x-2)³(x+1)(x²+x+1)/[(3-4x)(x²+x+2)]>0x²+x+1=(x+1/2)²+3/4>0x²+x+2=(x+1/2)²+7/4>0所以...