(1÷a-b-1÷a+b)÷b÷a²-2ab+b²
=(2b/[(a-b)(a+b)]÷[b÷(a-b)²]
=2b(a-b)²/[b(a-b)(a+b)]
=2(a-b)/(a+b)
=4√2/2
=2√2
先化简再求值1.当a=1+√2,b=1-√2时,求(1÷a-b-1÷a+b)÷b÷a²-2ab+b²的值
先化简再求值1.当a=1+√2,b=1-√2时,求(1÷a-b-1÷a+b)÷b÷a²-2ab+b²的值
数学人气:601 ℃时间:2020-03-30 02:36:38
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