求函数y=(x3-2)/[2(x-1)2]的极值!（x3表示x的三次方,(x-1)2表示(x-1)的平方）

y=(x^3-2)/[2(x-1)^2]y'=1/2*[3x^2(x-1)^2-(x^3-2)*2(x-1)]/(x-1)^4=1/2*[ 3x^2(x-1)-2(x^3-2)]/(x-1)^3=1/2*(x^3-3x^2+4)/(x-1)^3=1/2*(x^3+x^2-4x^2+4)/(x-1)^3=1/2*(x+1)(x-2)^2/(x-1)^3由y'=0,得：x=-1,2x=-1时,...