当x+π/4=2kπ+π/2 (k=0,±1,±2,.)时,y=sin(x+π/4)取得最大值,最大值为1
解得:x=2kπ+π/4 (k=0,±1,±2,.)
所以函数取得最大值时x的取值集合为:
{x|x=2kπ+π/4 ,k=0,±1,±2,.}
已知函数y=sin(x+π/4)求函数取得最大值时x的取值集合
已知函数y=sin(x+π/4)求函数取得最大值时x的取值集合
数学人气:351 ℃时间:2020-06-03 02:28:30
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