y=x²+px+8
y=(x+p/2)²+8-p²/4
顶点坐标为(-p/2,8-p²/4)
顶点在x正半轴上,
-p/2>0
p<0
8-p²/4=0
解得:p=-4√2
若抛物线y=x²+px+8的顶点在x正半轴上,那么p为?
若抛物线y=x²+px+8的顶点在x正半轴上,那么p为?
数学人气:303 ℃时间:2019-08-20 19:35:57
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