某数列第一项为1,并且对所有n大于或等于2,且都为N*,前n项积为n的平方,则通项公式?
某数列第一项为1,并且对所有n大于或等于2,且都为N*,前n项积为n的平方,则通项公式?
数学人气:473 ℃时间:2020-01-31 11:32:45
优质解答
n≥3时,a1a2…a(n-1)=(n-1)²,又a1a2…an=n²,两式相除,得:an=n²/(n-1)²,其中n≥3,a1=1,a1a2=2²=4,则a2=4【n=2时满足an=n²/(n-1)²】,则:an=1,(n=1);an=[n/(n-1)]²,n...
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