有一山峡宽1200米,两旁都是竖直徒壁,有一人在山峡内放一枪,头两次回声间隔5秒,则人离两壁的距离是?(设声速v=340米/秒)
有一山峡宽1200米,两旁都是竖直徒壁,有一人在山峡内放一枪,头两次回声间隔5秒,则人离两壁的距离是?(设声速v=340米/秒)
物理人气:944 ℃时间:2019-08-19 23:39:42
优质解答
设人第一次听到回声的时间t
1,到较近的峭壁的距离为s
1,
由v=
可得t
1=
=
;
设人第二次听到回声的时间t
2,到较远的峭壁的距离为s
2,则s
2=1200m-s
1,t
2=
=
,
由题知,t
2=t
1+5s,即:
=
+5s,
解得:s
1=1025m,
s
2=1200m-s
1=175m.
答:人离两壁的距离分别为1025m和175m.
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