令x=cost,变换方程d^2y/dx^2-x/(1-x^2)*dy/dx+y/(1-x^2)=0
令x=cost,变换方程d^2y/dx^2-x/(1-x^2)*dy/dx+y/(1-x^2)=0
答案是d^2y/dt^2+y=0,想看看解法
答案是d^2y/dt^2+y=0,想看看解法
数学人气:160 ℃时间:2019-08-18 06:29:00
优质解答
d^2y/dx^2=d(dy/dx)/dx=d(-dy/(sintdt))/(-sintdt)=(-(d^2y/dt*sint-dy/dt*cost)/(sint)^2)dt/(-sintdt)=d^2y/dt^2/(sint)^2-dy/dt*cost/(sint)^3原方程可化为1/(sint)^2*d^2y/dt^2-cost/(sint^3)*dy/dt+cost/(sint)...
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