已知3a-b+1的绝对值 +（3a-3/2b)方=0,则(b方/a+b)/【(b/a-b)*(ab/a+b）】的值为

3a-b+1的绝对值 +（3a-3/2b)方=0
∴3a-b+1=0
3a-3b/2=0
∴a=-1
b=-2
(b方/a+b)/【(b/a-b)*(ab/a+b）】
=b²/(a+b)×(a+b)(a-b)/ab²
=(a-b)/a
=(-1-2)/(-1)
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