我会
F(n)=ax^n+by^n
x,y是tt=pt+q两根
F(n)=pF(n-1)+qF(n-2)
F(3)=pF(2)+qF(1)
F(4)=pF(3)+qF(2)
p=-14
q=38
F(5)=20
若a,b,x,y满足ax+by=3,ax^2+by^2=7,ax^3+by^3=16,ax^4+by^4=42,求ax^5+by^5的值
若a,b,x,y满足ax+by=3,ax^2+by^2=7,ax^3+by^3=16,ax^4+by^4=42,求ax^5+by^5的值
数学人气:729 ℃时间:2020-03-20 16:08:50
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- 实数a,b,x,满足ax+by=3,ax^2+by^2=7,ax^3+by^3=16,ax^4+by^4=42,ax^5+by^5=?
- 若a,b,x,y满足ax+by=3,ax^2+by^2=7,ax^3+by^3=16,ax^4+by^4=42,求ax^5+by^5的值
- ax+bx=3,ax^2+by^2=7,ax^3+by^3=16,ax^4+by^4=42,求ax^5+bx^5.
- ax+bx=3,ax^2+by^2=7,ax^3+by^3=16,ax^4+by^4=42,求ax^5+bx^5.
- 已知:ax+by=3ax*2+by*2=7ax*3+by*3=16ax*4+by*4=42 ax*5+by*5=?
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