∵a²-3a+1=0
∴2a²-6a+2=0
∴2a²-5a=a-2
∵a²-3a+1=0
∴a²+1=3a
2a²-5a-2-3/(1+a²)
=a-2-2+3/3a
=a-4+1/a
=(a²+1-4a)/a
=(3a-4a)/a
=-a/a
=-1
不懂追问~
已知,a²-3a+1=0,则求2a²-5a-2-3/(1+a²）的值
已知,a²-3a+1=0,则求2a²-5a-2-3/(1+a²）的值
数学人气：203 ℃时间：2020-04-02 05:31:36
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