若A.B分别是双曲线的两个顶点,P为右支任意一点,直线PA,PB斜率分别为k1 k2

∵x^2/9-y^2/16=1∴x^2=9+(9/16)y^2且A(-3,0),B(3,0)设p(x1,y1)则k1=y1/x1+3,k2=y1/x1-3∴k1*k2=y1^2/(x1^2-9)∵p在双曲线上∴k1*k2=y1^2/[9+(9/16)y1^2-9]=y1^2/(9/16)y1^2=16/9你的命题有...