已知a,b,c为三角形ABC的三边长,且a+b+c=24,（c-a):(a+b):(c-b)=2:7:1,求a,b,c的值

因为（c - a):(a + b):(c - b) = 2:7:1 所以设 c - a = 2ka + b = 7kc - b = k解得：a = 3kb = 4kc = 5k因为 a + b + c = 24所以 3k + 4k + 5k = 2412k = 24k = 2所以:a = 3k = 6b = 4k = 8c = 5k = 10...