如图,在四边形ABCD中,角A＝135度,角B＝角D＝90度,BC＝2√3,AD＝2,求四边形ABCD的面积.

作AE//CD交BC于E,作EF//AD交CD于F则AEFD是平行四边形,且∠CFE=∠D=90EF=AD=2√3∠C=360-(∠A+∠B+∠D)=45CF=EF=2√3CE=√2*CF=√2*2√3=2√6BE=BC-CE=6-2√6易证∠BAE=45所以,AB=BE=6-2√6AE=√2BE=√2(6-2√6)=6√2...