已知平面直角坐标系中,点O为原点,A(-3,-4),B(5,-12),若OC=OA+OB,OD=OA-OB.(Ⅰ)求点C和点D的坐标;(Ⅱ)求OC•OD.

已知平面直角坐标系中,点O为原点,A(-3,-4),B(5,-12),若
OC
=
OA
+
OB
OD
=
OA
-
OB

(Ⅰ)求点C和点D的坐标;
(Ⅱ)求
OC
OD
数学人气:199 ℃时间:2019-08-20 04:33:04
优质解答
(Ⅰ)∵
OA
=(-3,-4),
OB
=(5,-12),
OC
=
OA
+
OB
=(-3+5,-4-12)=(2,-16),
OD
=
OA
-
OB
=(-3-5,-4+12)=(-8,8);
∴点C(2,-16),点D(-8,8);
(Ⅱ)
OC
OD
=2×(-8)+(-16)×8=-144.
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