已知等比数列{an}中,首项是81,数列{bn}满足bn=logan,其前n项和Sn.

(1)等比数列｛an},首项为81
设an=a1*q^(n-1)=81*q^(n-1)
数列{bn}满足bn=log3为底an
∴bn=log3为底[81*q^(n-1)]=log3为底81+log3为底q^(n-1)
=4+(n-1)log3为底q
=log3为底q*n+4-log3为底q
∵log3为底q为常数,∴bn为以4为首项,log3为底q为公差的等差数列
（2）若S11≠S12,且S11最大,
∴b11＞0,b12＜0
于是bn=n*d+4-d
∴10d+4＞0,11d+4＜0
∴-2/5＜d＜-4/11