设鸵鸟X只,斑马Y只
X+Y=107
4Y=2X+56
解得 X=62 Y=45
即鸵鸟62只,斑马45只
动物园有鸵鸟和斑马共107只,斑马的脚数比鸵鸟多56只.两种动物各多少只?
动物园有鸵鸟和斑马共107只,斑马的脚数比鸵鸟多56只.两种动物各多少只?
数学人气：633 ℃时间：2020-04-20 21:30:25
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