证明tan(3x/2)-tan(x/2)=(2sinx)/(cosx+cos2x)
证明tan(3x/2)-tan(x/2)=(2sinx)/(cosx+cos2x)
请各位大侠相助!
请各位大侠相助!
数学人气：109 ℃时间：2020-06-11 08:19:30
优质解答
tan(3x/2)-tan(x/2) =sin(3x/2)/cos(3x/2)-sin(x/2)/cos(x/2)(通分) =[sin(3x/2)cos(x/2)-cos(3x/2)sin(x/2)]/[cos(3x/2)cos(x/2)] =sin(3x/2-x/2]/[(1/2)(cos2x+cosx)(积化和差) =2sinx/(cosx+cos2x) 故原式成立....
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