已a2+b2-2a+6b+10=0,求a2006−1/b的值.
已a
2+b
2-2a+6b+10=0,求
a2006−的值.
数学人气:410 ℃时间:2019-10-08 18:41:08
优质解答
∵a
2+b
2-2a+6b+10=(a-1)
2+(b+3)
2=0,
∴a-1=0,b+3=0,即a=1,b=-3,
则原式=1+
=
.
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