求与圆x²+y²-3x+5y-1=0圆心相同,且过点M(1,2)的圆的方程,请写出过程

圆:x^2-3x+(3/2)^2+y^2+5y+(5/2)^2=(3/2)^2+(5/2)^2+1-> (x-3/2)^2+(y-5/2)^2=19/2 -> 圆心为(3/2,5/2)半径R=√[(3/2-1)^2+(5/2-2)^2]=√2/2所以方程为(x-3/2)^2+(y-5/2)^2=1/2