x\x+1的平方-5x\x+1+6=0

答：[x/(x+1)]²-5x/(x+1)+6=0 把x/(x+1)看成整体用十字相乘法分[x/(x+1)-2]*[x/(x+1)-3]=0x/(x+1)=2或者x/(x+1)=3所以：x=2x+2还活着x=3x+3解得：x=-2或者x=-3/2经检验,x=-2或者x=-3/2都是原分式方程的根x/(x+1...