g(x)是单调可导函数f(x)的反函数 f(1)=2,f'(1)=-1/√3,f''(1)=1,求g''(x)=?麻烦写出过程

设y=f(x)
则g''(y)=d(dx/dy)/dy
=d(dx/dy)/dx * dx/dy
=d(1/(dy/dx))/dx * 1/(dy/dx)
=-f''(x)/[f'(x)]^2 * 1/f'(x)
=-f''(x)/[f'(x)]^3
所以g''(2)=3√3