x/(ax-a^2)=[(x-a)+a]/[x(x-a)]=1/a+1/(x-a)
y/(ay-a^2)、z/(az-a^2)作同样分解,相加即得
x/(ax-a^2)+y/(ay-a^2)+z/(az-a^2)=1/(x-a)+1/(y-a)+1/(z-a)+3/a
x/(ax-a^2)+y/(ay-a^2)+z/(az-a^2)=1/(x-a)+1/(y-a)+1/(z-a)+3/a
数学人气：540 ℃时间：2020-03-27 16:39:38
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