移项得 X-XA=A ,
X(E-A)=A ,
因此 X=A*(E-A)^(-1) ,
计算可得 (E-A)^(-1)=(0 -1/2 0 ;2 -3/4 -1/2 ;-1 0 0),
因此 X=A*(E-A)^(-1)=(-1 -1/2 0 ;2 -7/4 -1/2 ;-1 0 -1).
设矩阵,A=|1 0 1| |2 1 0| |-3 2 5|(三行三列)求满足方程X-A=XA的矩阵X
设矩阵,A=|1 0 1| |2 1 0| |-3 2 5|(三行三列)求满足方程X-A=XA的矩阵X
数学人气:527 ℃时间:2020-04-17 10:43:52
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