∫dx/(x√(a^2-x^2))
∫dx/(x√(a^2-x^2))
数学人气:703 ℃时间:2020-05-27 03:23:29
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令x=a*sint(t在0到pi/2之间)则dx=a*cost*dt√(a^2-x^2)=√{a^2[1-(sint)^2]}=a*cost原式=∫ a*cost*dt/(a*sint*a*cost)=∫ dt/(a*sint)=1/a*∫ sint*dt/(sint)^2= -1/a*∫ d(cost)/[1-(cost)^2]= -1/a*∫ d(cost)*...
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