一道求函数值的题
一道求函数值的题
已知f(x)=x²+1,求f(a+1)的值
已知f(x)=x²+1,求f(a+1)的值
数学人气:499 ℃时间:2020-08-11 09:23:30
优质解答
f(a+1)=(a+1)²+1=a²+2a+2
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