原式=1/a-1/(a+1)+1/(a+1)-1/(a+2)+……+1/(a+2009)-1/(a+2010)
=1/a-1/(a+2010)
=2010/a(a+2010)
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)……1/(a+2009)(a+2010)怎么解
1/a(a+1)+1/(a+1)(a+2)+1/(a+2)(a+3)……1/(a+2009)(a+2010)怎么解
数学人气：619 ℃时间：2020-02-01 05:51:36
优质解答
我来回答
类似推荐
猜你喜欢