计算：根号1-1/a^2乘以根号a-2a/a+1,其中a>1

√(1-1/a²)*√[a-2a/(a+1)]因为1-1/a²≥0,a-2a/(a+1) ≥0a>1联解上面的不等式组可得a>1√(1-1/a²)*√[a-2a/(a+1)]=√[(a²-1)/a²]*√{[a(a+1)-2a]/(a+1)}=√[(a²-1)/a²]*√[(a
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