将抛物线y=x^2+1沿射线y=1/2x-1(x大于等于0)方向平移根号5个单位,其函数解析式变为?
将抛物线y=x^2+1沿射线y=1/2x-1(x大于等于0)方向平移根号5个单位,其函数解析式变为?
数学人气：495 ℃时间：2019-11-05 22:01:05
优质解答
y=x^2+7/4,线y=x^2+1与y=1/2x+a组成方程组即x^2+1-1/2x-a=0,a=3/4,沿射线y=1/2x-1(x大于等于0)方向平移根号5个单位即沿y轴在（0,3/4）基础上平移一个单位.所以y=x^2+7/4
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