方程4的x次方+2的x+1次方+m+4=0可化为
(2的x次方)^2+2*(2的x次方)+m+4=0
设(2的x次方)=y.则原方程化为y^2+2y+m+4=.
由题意得▲=4-4(m+4)=-4m-12>=0得m0,所以【-2+根号(-4m-12)】/2>0解得m
已知方程4的x次方+2的x+1次方+m+4=0有实数解,求实数m的取值范围
已知方程4的x次方+2的x+1次方+m+4=0有实数解,求实数m的取值范围
数学人气:355 ℃时间:2019-08-20 22:33:41
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