急,已知函数f(x)=cos^2wx=√3sinwx*coswx,(w>0)的最小正周期为π求（1）f(π/3)

f(x)=cos^2wx+√3sinwx*coswx=(1+cos2wx)/2+√3/2sin2wx=√3/2sin2wx+1/2cos2wx+1/2=sin(2wx+π/6)+1/2最小正周期为π 最小正周期=2π/2w=π w=1f(x)=sin(2x+π/6)+1/2（1）f(π/3)=sin(2π/3+π/6)+1/2=sin5π/6+1/...