（线性代数）设A,B为n阶方阵,证明:r(AB)>=r(A)+r(B)-n
（线性代数）设A,B为n阶方阵,证明:r(AB)>=r(A)+r(B)-n
数学人气：113 ℃时间：2020-03-29 01:57:35
优质解答
证明：AB与n阶单位矩阵En构造分块矩阵 |AB O| |O En| A分乘下面两块矩阵加到上面两块矩阵,有 |AB A| |0 En| 右边两块矩阵分乘-B加到左边两块矩阵,有 |0 A | |-B En| 所以,r(AB)+n=r(第一个矩阵)＝r(最后一个矩阵)>=r...
我来回答
类似推荐
猜你喜欢
- 1We should try ____ the old people,because we will be old in the future,too.A to polite to
- 2Do you think the biographer likes or dislikes the person whose life story is being told?
- 3关于化学反应速率的计算
- 4W: If anybody wants tickets for Saturday’s game, let me know. My roommate has two
- 5ca3( po4 )2溶解性?
- 6he who has neve deen to the great wall is not a ture man
- 7紫藤萝瀑布 阅读这句话富有人生哲理,结合你自己的生活经历或阅读体验,谈谈你对这句话的理解.
- 81.They can't have thought that i was at home then,
- 9一道关于数学导数的题
- 10两个相邻的自然数的积是1260求这两个自然数