x²-2x-4＜[x-3]-[x＋1] []为绝对值 谁会解

x^2-2x-4 ＜ |x-3| - |x+1|如果x＜-1：x^2-2x-4 ＜ 3-x +(x+1) = 4x^2-2x-8＜0(x+2)(x-4)＜0-2＜x＜4又：x＜-1∴-2＜x＜-1如果-1≤x≤3：x^2-2x-4 ＜ 3-x -(x+1) = 2-2xx^2＜6-√6＜x＜√6又：-1≤x≤3∴-1≤x≤√6...