1/【sec(x+y)-1】的导数是什么?
1/【sec(x+y)-1】的导数是什么?
数学人气:625 ℃时间:2019-08-07 21:02:37
优质解答
表达式=1/[1/cos(x+y)-1]=cos(x+y)/[1-cos(x+y)]则导数=[-sin(x+y)(1+y')+cos(x+y)sin(x+y)(1+y')]/[1-cos(x+y)]^2=sin(x+y){[cos(x+y)-1]y'+cos(x+y)-1}/[1-cos(x+y)]^2=sin(x+y)(y'+1)/[cos(x+y)-1].
我来回答
类似推荐