[log3（4）+log根下3（2）][log2(9)+log4(根3)]

[log3（4）+log根下3（2）][log2(9)+log4(根3)]
=[lg4/lg3+lg2/lg根下3][lg9/lg2+lg根3/lg4]
=[2lg2/lg3+2lg2/lg3][2lg3/lg2+1/4lg3/lg2]
=4lg2/lg3*9/4lg3/lg2
=9答案是对的，解法没看明白。题目是（log以3为底4的对数+log以根3为底2的对数）（log以2为底9的对数+log以4为底根3的对数）主要是利用换底公式loga(b)=lgb/lga