sin(25π/12)cos(11π/6)-cos(11π/12)sin(5π/6)
=sin(2π+π/12)cos(2π-π/6)-cos(π-π/12)sin(π-π/6)
=sin(π/12)cos(π/6)+cos(π/12)sin(π/6)
=sin(π/12+π/6)
=sin(π/4)
=√2/2
化简sin(25π/12)cos(11π/6)-cos(11π/12)sin(5π/6)的值是
化简sin(25π/12)cos(11π/6)-cos(11π/12)sin(5π/6)的值是
数学人气:144 ℃时间:2020-04-05 18:24:27
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