若集合A={α|180K+30<α<180K +90,K∈Z},集合B={β|360k+315<β<360k+405,k∈Z},求A∩B
若集合A={α|180K+30<α<180K +90,K∈Z},集合B={β|360k+315<β<360k+405,k∈Z},求A∩B
数学人气:279 ℃时间:2019-10-18 02:26:10
优质解答
α ,180K+30<α<180K +90等价于360k+30<α<360k+90,且180(2K+1)+30<α<180(2K+1)+90,即360k+210<α<360k+270故A={α|360k+30<α<360k+90且360k+210<α<360k+270k∈Z}.β ,360k+315<β<360k...你是高一的吧恩你呢大一哇
我来回答
类似推荐