将一根长为56cm的铁丝剪成两两段,围成两个正方形,要使两个正方形面积和为100cm^2,该怎么剪?

假设其中1段长为xcm,那么另外一段长56-x cm那么总面积y= (x/4)^2+((56-x)/4)^2=(x^2+x^2-112x+3136)/16=(x^2-56x+1568)/8y=100(x^2-56x+1568)/8=100x^2-56x+1568=800x^2-56x+768=0(x-24)(x-32)=0x=24,32所以剪成24cm...