已知1+tan/1-tan=3+2根号2,求(sin^2x+根号2sinxcosx-cos^2)/(sin^2+2cos^2)的值
已知1+tan/1-tan=3+2根号2,求(sin^2x+根号2sinxcosx-cos^2)/(sin^2+2cos^2)的值
数学人气:203 ℃时间:2020-03-15 02:59:46
优质解答
(1+tanx)/(1-tanx)=3+2根号21+tanx = (3+2根号2) - (3+2根号)tanx2(2+根号2)tanx = 2(根号2+1)tanx = (根号2+1) / (2+根号2) = 根号2/2(sin^2x+根号2sinxcosx-cos^2)/(sin^2x+2cos^2x)分子分母同除以cos^2x:= (...
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