化简后求值 [(x-2y)²+(x-2y)(x-2y)-2x(2x-y)]÷2x 其中x=2 y=3

[[(x-2y)²+(x-2y)(x-2y)-2x(2x-y)]÷2x =(x^2-4xy+4y^2+x^2-4xy+4y^2-4x^2+2xy)÷2x=(-2x^2-6xy+8y^2)÷2x=-x-3y+4y^2/x=-2-9+18=7但我觉得原题可能是(x-2y)²+(x+2y)(x-2y)-2x(2x-y)]÷2x 那么原式=(x-2y)...