√x+ √(1/x)= √6
两边平方:x+1/x+2=6
则x+1/x-2=2
(√x-√(1/x))^2=2
故 √x-√(1/x)= √2或- √2
若根号下x+根号下x分之1=根号下6则根号下x-根号下x分之1?
若根号下x+根号下x分之1=根号下6则根号下x-根号下x分之1?
数学人气:802 ℃时间:2020-05-08 00:47:23
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