已知圆C:x^2+(y-1)^2=5,直线:mx-y+1-m=0 设L与圆C交于A.B两点,求AB中点M的轨迹方程
已知圆C:x^2+(y-1)^2=5,直线:mx-y+1-m=0 设L与圆C交于A.B两点,求AB中点M的轨迹方程
数学人气:691 ℃时间:2020-02-06 01:21:34
优质解答
圆心C(0,1)到直线L的距离d=|-m|/√(m²+1)
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