limx趋近于负八时根号1-x再减去3除以三次根号x加2的极限

[√(1-x)-3]×[√(1-x)+3] = -x-8 ①[³√(x)+2]×[x^(2/3)+4-2x^(1/3)] = x+8 ②由①÷②可得：[√(1-x)-3] / [³√(x)+2] = -[x^(2/3)+4-2x^(1/3)] / [√(1-x)+3]然后直接将x=-8代进去可得结果为-2...