[(x-2)^3-(x-1)^2+1]/(x-2)=[x^3-6x^2+12x-8-x^2+2x-1+1]/(x-2)
=[x^3-7x^2+14x-8]/(x-2)=[(x-2)(x^2+2x+4)-7x(x-2)]/(x-2)
=x^2-5x+4=2004+4=2008
已知x^2-5x-2004=0,求代数式(x-2)^3-(x-1)^2+1除以x-2
已知x^2-5x-2004=0,求代数式(x-2)^3-(x-1)^2+1除以x-2
数学人气:153 ℃时间:2019-09-20 12:59:58
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